Find the degree of x square - 2x+1=xqube
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0 is the degree of x^2
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Given equation->x²-2x+1=x³
Transpositioning x³
-x³+x²-2x+1=0
-1(x³-x²+2x-1) =0
x³-x²+2x-1=0
Here,
Degree of the equation=3
Hope this helps you!
Transpositioning x³
-x³+x²-2x+1=0
-1(x³-x²+2x-1) =0
x³-x²+2x-1=0
Here,
Degree of the equation=3
Hope this helps you!
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