find the demensional formula for E=m²c
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1
Answer:
Since, k=
4πϵ
0
1
,
dimension of [ϵ
0
]=[k
−1
]=[ML
3
T
−4
A
−2
]
−1
=[M
−1
L
−3
T
4
A
2
]
Also we know that , c=
(
μ
0
ϵ
0
)
1
this gives , dimension of [μ
0
]=[c
2
ϵ
0
]
−1
=[MLT
−2
A
2
]
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