Question

find the denominator of 8/√11-√7​

Answer 1

Answer:

Heya !!

8 / √11–√7

=> 8/ (√11–√7) × (√11+√7) / (√11+√7)

=> [8(√11–√7)] / (11–7)

=> (8√11–4√7) / 8

=> (√11 – √7) / 8

Answer 2

Hope this helps you ;)

$\frac{8}{ \sqrt{11} - \sqrt{7} }$

$= \frac{8}{ \sqrt{11} - \sqrt{7} } \times \frac{( \sqrt{11} + \sqrt{7} )}{( \sqrt{11} + \sqrt{7}) }$

$= \frac{8( \sqrt{11} + \sqrt{7} ) }{ { \sqrt{11} }^{2} - { \sqrt{7} }^{2} }$

$= \frac{8( \sqrt{11} + \sqrt{7} )}{11 - 7}$

$= {2 (\sqrt{11} + \sqrt{7}) }$

$= {2\sqrt{11}+ 2\sqrt{7} }$