Find the density of a 3.6m sulphuric acid
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Hi mate....
Here we go........
Molarity of acid = 3.6;Molar mass of H2SO4 = 98g. Mass of H2SO4 present in 1 L (1000 mL) of acid = 3.6 x 98 g = 352.8 g.
Let d be the density of the acid. Density = Mass/Volume Mass of 1000 mL of acid = (d x 1000) g
Percentage of H2SO4 in acid = 29352.9 x 100/1000 d =
29352.9/10 d = 29290 d = 352.9Therefore d = 352.9/290= 1.217 g/mL
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