find the deriative of cosec x -cot x
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Answer:
Let y = cosec x cot x ∴ d y d x = d d x [ c o s e c x c o t x ] dydx=ddx[cosecxcotx] = ( d d x c o s e c x ) c o t x + c o s e c x d d x c o t x =(ddxcosecx)cotx+cosecxddxcotx = cot x ∙(− cot x cosec x) + cosec x (- cosec2x) = − cot2x cosec − cosec3x = −cosec x (cot2x + cosec2x)Read more on Sarthaks.com - https://www.sarthaks.com/1038632/find-the-derivative-of-cosec-x-cot-x
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Answer:
cosec x[cosec(x) - cot(x)]
Step-by-step explanation:
cosec x - cot x
= d/dx(cosec x - cot x)
=cosec²x - cot(x)cosec(x)
=cosec x[cosec(x) - cot(x)]
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