Question

find the derivate of the function y defined implicity by the equation x4 +y4- a^ xy=0​

Answer 1

Answer:

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Answer 2

$\large { \underline{ \bf \red{Question:- }}}$

find the derivate of the function y defined implicity by the equation x4 +y4- a^ xy=0

$\large { \underline{ \bf \purple{Solution:- }}}$

$Given, \: \: x⁴ + y⁴ - a²xy = 0 \\ x⁴ + y⁴ = a²xy \\ Differentiate \: \: both \: \: sides \: \: w.r.t  \: \: x  \: \: we \: \: get, \\ 4x³ + 4y³ \frac{dy}{dx} \\ a²x \frac{dy}{dx} + a²y \\ therefore , \frac{dy}{dx} = \frac{a²y - 4x³ }{4y³ -a²x } \\ = - \frac{4x³ -a²y }{4y³ -a²x } </p><p></p><p>$

$\large { \underline{ \bf \pink{Therefore:- }}}$

$- \frac{4x³ -a²y }{4y³ -a²x } \: \: is \: \: the \: \: Correct \: \: Answer.$