Question

Find the derivatie by using first principle sin(2x-3)

Answer 1

Answer:

hope this helps

Step-by-step explanation:

Let y = sin(2x+3)⇒

y + Δy = sin[2(x+Δx) + 3]⇒

Δy =sin[2(x+Δx) + 3] − sin(2x+3)

⇒Δy = 2 cos (2x+Δx+3) . sin(Δx)

⇒ΔyΔx =  2 cos (2x+Δx+3) . sin(Δx)Δx

⇒limΔx→0ΔyΔx = 2 limΔx→0cos (2x+Δx+3) × limΔx→0sin(Δx)Δx

⇒dydx = 2 cos(2x+3) ×1 = 2 cos(2x+3)