find the derivation of y=2x -3/4
Answers
Answered by
0
Answer:
Step-by-step explanation:
ANSWER
Solution:-
Given:- y=(2x+3)
(3x−5)
To find:-
dx
dy
=?
y=(2x+3)
(3x−5)
Taking log both sides, we have
logy=log((2x+3)
(3x−5)
)
logy=(3x−5)log(2x+3)
Now, differentiating both sides w.r.t. x, we have
dx
d
(logy)=(3x−5).
dx
d
(log(2x+3))+(log(2x+3)).
dx
d
(3x−5)
y
1
dx
dy
=(3x−5)(
2x+3
1
.2)+(log(2x+3))(3)
dx
dy
=y(
2x+3
2(3x−5)
+3log(2x+3))
⇒
dx
dy
=((2x+3)
(3x−5)
)(
2x+3
(6x−10)
+3log(2x+3))
Similar questions