Math, asked by Anonymous, 7 months ago

find the derivative for y=x^4+2x^-2+x^7+1 ​

Answers

Answered by mathdude500
4

Question :-

Find the Derivative of

\bf \:y =  {x}^{4}  +  {2x}^{ - 2}  +  {x}^{7} + 1

Answer

Given :-

\bf \:y =  {x}^{4}  +  {2x}^{ - 2}  +  {x}^{7} + 1

To find :-

\bf \:\dfrac{dy}{dx}

Formula used :-

\bf \:\dfrac{d}{dx}  {x}^{n}  = n {x}^{n - 1}

\bf \:\dfrac{d}{dx} k = 0

Solution :-

\bf \:y =  {x}^{4}  +  {2x}^{ - 2}  +  {x}^{7} + 1

Differentiate w. r. t. x, we get

\bf\implies \:\dfrac{d}{dx} \bf \:y =\dfrac{d}{dx} (  {x}^{4}  +  {2x}^{ - 2}  +  {x}^{7} + 1 )

\bf\implies \:\dfrac{dy}{dx} =  \dfrac{d}{dx}  {x}^{4}  + \dfrac{d}{dx} {2x}^{ - 2}  +  \dfrac{d}{dx} {x}^{7}   + \dfrac{d}{dx} 1

\bf\implies \:\dfrac{dy}{dx}  =  {4x}^{3}  -  {4x}^{ - 3}  +  {7x}^{6}

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Answered by suman8615
3

Answer:

this is correct..........................

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