Question

find the derivative for y=x^4+2x^-2+x^7+1 ​

Answer 1

Question :-

Find the Derivative of

$\bf \:y = {x}^{4} + {2x}^{ - 2} + {x}^{7} + 1$

Answer

Given :-

$\bf \:y = {x}^{4} + {2x}^{ - 2} + {x}^{7} + 1$

To find :-

$\bf \:\dfrac{dy}{dx}$

Formula used :-

$\bf \:\dfrac{d}{dx} {x}^{n} = n {x}^{n - 1}$

$\bf \:\dfrac{d}{dx} k = 0$

Solution :-

$\bf \:y = {x}^{4} + {2x}^{ - 2} + {x}^{7} + 1$

Differentiate w. r. t. x, we get

$\bf\implies \:\dfrac{d}{dx} \bf \:y =\dfrac{d}{dx} ( {x}^{4} + {2x}^{ - 2} + {x}^{7} + 1 )$

$\bf\implies \:\dfrac{dy}{dx} = \dfrac{d}{dx} {x}^{4} + \dfrac{d}{dx} {2x}^{ - 2} + \dfrac{d}{dx} {x}^{7} + \dfrac{d}{dx} 1$

$\bf\implies \:\dfrac{dy}{dx} = {4x}^{3} - {4x}^{ - 3} + {7x}^{6}$

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Answer 2

Answer:

this is correct..........................