Question

Find the derivative from the first principle cos³x​

Answer 1

i dont know ok ok ok ok ok

1

1

1

1

1

2

2

349r0r0r0e002202928273849r0y

Answer 2

Answer:

f′(x)=h→0limhf(x+h)−f(x)

=h→0limhcos(x+h)−cosx

=h→0lim[hcosxcosh−sinxsinh−cosx]

=h→0lim[h−cosx(1−cosh)−sinxsinh]

=h→0lim[h−cosx(1−cosh)=hsinxsinh]

=−cosx(h→0limh1−cosh)−sinxh→0lim(hsinh)

=−cosx.(0)−sinx(1)=−sinx

Step-by-step explanation:

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