find the derivative of (2x²-5√x+3)(3x-4√x) ?
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Answered by
1
Answer:
y=
3x
2
+4x+5
(x−3)(x
2
+4)
Taking log on both sides
logy=
2
1
log[
3x
2
+4x+5
(x−3)(x
2
+4)
]
⇒logy=
2
1
[log(x−3)+log(x
2
+4)−log(3x
2
+4x+5)]
Differentiating w.r.t.x
y
1
dx
dy
=
2
1
[
x−3
1
+
x
2
+4
1
×2x−
3x
2
+4x+5
1(6x+4)
]
⇒
dx
dy
=
2
1
3x
2
+4x+5
(x−3)(x
2
+4)
[
x−3
1
+
x
2
+4
2x
−
3x
2
+4x+5
6x+4
]
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