Question

Find the derivative of ( 3 - 4x )^7​

Answer 1

Answer:

$\frac{d}{dx} (3-4x)^{7} = -28 (3-4x)^{6}$

Step-by-step explanation:

We have the standard result,

$\frac{d}{dx} (f(x))^{n} =n(f(x))^{n-1} f'(x)$

here $f(x)=3-4x$,

therefore $f'(x)=-4$

and, $f(x)^{n} =(3-4x)^{7}$

hence $nf(x)^{n-1}=7(3-4x)^{6}$, substituting all these

$\frac{d}{dx}(3-4x)^{7} =7(3-4x)^{6} *-4$

                  $=-28(3-4x)^{6}$.

Hence the answer

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