Question

find the derivative of "4/Cosx + 1/Tanx"​

Answer 1

Step-by-step explanation:

We have,

$y = \frac{4}{ \cos( x ) } + \frac{1}{ \tan(x) }$

$= > y = 4 \sec(x) + \cot(x)$

Differentiating both wrt x, we get,

$\frac{dy}{dx} = 4 \sec(x)\tan(x) + ( - \csc^{2} (x) )$

$= > \frac{dy}{dx} = 4 \sec(x) \tan(x) - \csc^{2} (x)$