Question

find the derivative of 9 × 2^x​

Answer 1

Answer:

9* log2 * 2^x

Step-by-step explanation:

let y = 9* 2^x

y/9 = 2^x

logrithm both side

log y - log 9 = x * log 2

differentiate both side

1 dy/ ydx = log2

dy / dx = log2 * y

dy/dx = log2 * 9 * 2^x