Question

Find the derivative of:
a*+e*+logx+3x+9are x
​

Answer 1

Answer:

$\frac{dy}{dx} = {a}^{x} loga + {e}^{x} + \frac{1}{x} + 3 + 0$

Step-by-step explanation:

let the above expression be equal to y.

On differentiating wrt. x we get

$\frac{dy}{dx} = {a}^{x} loga + {e}^{x} + \frac{1}{x} + 3 + 0$

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