Find the derivative of a^ lnx
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2
y=a^lnx
dy/dx= a^lnx.log a × dy/dx lnx
dy/dx=a^lnx .log a.1/x
arpit7280:
aita thik achi ?
Answered by
6
Hey mate....
Here is your answer....
y = a^Inx
dy/dx = a^ Inx. log a X dy / dx Inx
dy/dx = a^Inx.log a. I/x
Hope it may helps you... :)
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