Question

Find the derivative of (ax^2 + bx +c)^100 from first principle.​

Answer 1

Answer:

Step-by-step explanation:

By the Sum Rule, the derivative of ax2+bx+c a x 2 + b x + c with respect to a is dda[ax2]+dda[bx]+dda[c] d d a [ a x 2 ] + d d a [ b x ] + d d a [ c ] .

Answer 2

200ax+100b .

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