Question

find the derivative of..
(ax + b)^5​

Answer 1

Answer:

5a(ax+b)⁴

Step-by-step explanation:

d(ax+b)⁵/dx

5(ax+b)⁴ d(ax+b)/dx

5(ax+b)⁴ (a)

5a(ax+b)⁴

Answer 2

Answer:

Take y as (ax+b)^5

$\frac{dy}{dx} = 5 {(ax + b)}^{4} \: \: \: \: \: \: \: \: \: \: \: \: (using \: {x}^{n} = n {x}^{n - 1} \: where \: x = (ax + b) \: and \: n = 5)$

$\frac{dy}{dx} = 5 {(ax + b)}^{4} .a \: \: \: \: \: \: \: \: \: \: (differentiating \: (ax + b))$

$\frac{dy}{dx} = 5a {(ax + b)}^{4}$

So answer is 5a(ax+b)^4