Math, asked by Kamilmalik, 1 year ago

find the derivative of cot(3x-2) with respect to x from First principle of derivatives.

Answers

Answered by rishab1132
1

bhai aaj tera bhi math ka paper tha

Answered by throwdolbeau
0

Answer:

The derivative of f(x) = cot(3x-2) is found to be f'(x) = -3cosec²(3x - 2)  

Step-by-step explanation:

The function f(x) is given to be cot(3x - 2)

Now, we need to find the derivative of this given function f(x) or we need to find f'(x)

⇒ f(x) = cot(3x - 2)

Differentiating the function f(x) with respect to x

⇒ f'(x) = -cosec²(3x - 2) × Derivative of (3x - 2) with respect to x

⇒ f'(x) = -cosec²(3x - 2) × 3

⇒ f'(x) = -3cosec²(3x - 2)

Hence, The derivative of f(x) = cot(3x-2) is found to be f'(x) = -3cosec²(3x - 2)

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