find the derivative of cot x using first principle
Answers
Answered by
1
Step-by-step explanation:
Given,
dx
d
cotx
=
dx
d
(
sinx
cosx
)
=
sin
2
x
sinx
dx
d
cosx−cosx
dx
d
sinx
=
sin
2
x
sinx(−sinx)−cosx(cosx)
=
sin
2
x
−sin
2
x−cos
2
x
=−(
sin
2
x
sin
2
x+cos
2
x
)
=−
sin
2
x
1
=− cosec
2
x.
Answered by
0
Answer:
ANSWER
Given,
dx
d
cotx
=
dx
d
(
sinx
cosx
)
=
sin
2
x
sinx
dx
d
cosx−cosx
dx
d
sinx
=
sin
2
x
sinx(−sinx)−cosx(cosx)
=
sin
2
x
−sin
2
x−cos
2
x
=−(
sin
2
x
sin
2
x+cos
2
x
)
=−
sin
2
x
1
=− cosec
2
x.
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