Find the derivative of cube root of (sin x) using first principle?
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the derivative of cube root of sin X is
d(sin*1/3 X )/dx
= 1/3 × sin*1/3 -1( X )
= 1/[3×sin*2/3(X)].......✓✓
d(sin*1/3 X )/dx
= 1/3 × sin*1/3 -1( X )
= 1/[3×sin*2/3(X)].......✓✓
naveenbet:
Hey I can answer any derivative using your formula. Answer me using first principle/definition method.
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