Math, asked by harshalabhujade25, 3 months ago

find the derivative of ex sin(x²)

Answers

Answered by BadCaption01
1

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{ \bold { \underline{\large\pink{Correct \: Question : - }}}} \:

Find the derivative of the function given by F(x)=Sin x2

{ \bold { \underline{\large\red{Answer: - }}}} \:

let y = sin (x)  ^ { 2  }

we need to find derivative of your, w. r. t. x

I.e \frac{ dy  }{ dx  }  = \frac{ d( \sin (  x  ^ { 2  }     )    }{ dx  }

=  \cos (  x  ^ { 2  }     )  . \frac{ d(x  ^ { 2  }  )  }{ dx  }((  ^ { sin  }   \theta)'= { Cos  }   \theta)

= \cos (  x  ^ { 2  }     )  .(2x  ^ { 2  }  -1)

= \cos (  x  ^ { 2  }     )  (2x)

= 2x.Cos x  ^ { 2  }

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\huge\mathfrak\purple{➛} Trigonometry table :)

\begin{gathered}\begin{gathered}\begin{gathered}\sf Trigonometry\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm \infty \\ \\ \rm cosec A & \rm \infty & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm \infty \\ \\ \rm cot A & \rm \infty & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0\end{array}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}

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