Find the derivative of f(x)= 1+ x + x² + x⁴
at x =2
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Answer:
f(x)= 1+ x + x² + x⁴
difff . w. r. to x
d(f(x))/dx = 0 + 1 + 2x + 4x^3
put x=2
d(f(2))/dx = 0 + 1 + 2*2 + 4*2^3
=>d(f(2))/dx = 1 + 4 + 32
=>d(f(2))/dx = 37
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