Math, asked by shuvangana1737, 1 month ago

Find the derivative of f(x) = 2x^2 + 4x + 5 at x = 2​

Answers

Answered by mekakann
0

Answer:

13

Step-by-step explanation:

given above, hope it helps

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Answered by SrijanAdhikari23
0

The derivative of the function is  f(x) = 2x^2 + 4x + 5  at x = 2 is 12.

The derivative of a function is the instantaneous rate of change of the function at a particular point. It can also be defined as the slope of the tangent to the graph of the functions at any specified point.

the given function is f(x) = 2x^2 + 4x + 5 .

We have to use the basic power rule to differentiate the function:

The power rule states that :

If a function is defined as  g(x)=x^n ,(n\in R)  then the derivative of the function is given by:

g'(x)=nx^{n-1}  

In the above function we will use the same rule to find the derivative:

f(x) = 2x^2 + 4x + 5\\or, f'(x)=2\times2x^{2-1}+(1\times 4)x^{1-1}+0\\or,f'(x)=4x+4

Hence the derivative of the function is f'(x)=4x+4 .

Now we have to find the value of the derivative at x=2 .

f'(2)=4\times 2+4\\or,f'(2)=12

Therefore the value of the derivative of the function at x=2 is 12.

Learn more about the derivative of a function at:

https://brainly.in/question/49659444

https://brainly.in/question/52261849

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