Math, asked by EnchantingPrince, 5 days ago

find the derivative of f(x) = X+1/x-1​

Answers

Answered by ramkotichandu
2

Answer:

f'(x)=x-X-2

---------

(x-1)^2

Step-by-step explanation:

f'(x)=(x-1)*1-(X+1)*1

-------------------

(x-1)^2

=x-X-2

---------

(x-1)^2

Answered by MysticSohamS
2

Answer:

your solution is as follows

pls mark it as brainliest

Step-by-step explanation:

to \: find :  \frac{d}{dx} \:  f(x) =  \frac{x + 1}{x - 1}  \\  \\ we \: know \: that \\ according \: to \: quotient \: rule \\ of \: differentiation \\  \\  \frac{d}{dx} ( \frac{u}{v} ) =  \frac{v. \frac{d}{dx}  (u)  - u. \frac{d}{dx} (v)}{v {}^{2} }  \\  \\  =  \frac{(x - 1). \frac{d}{dx} (x + 1) - (x + 1). \frac{d}{dx} (x - 1)}{(x - 1) {}^{2} }  \\  \\  =  \frac{(x - 1).1 - (x + 1).1}{(x - 1) {}^{2} }  \\  \\  =  \frac{x - 1 - x - 1}{(x - 1) {}^{2} }  \\  \\  =  -  \frac{2}{(x - 1) {}^{2} }

Similar questions