Math, asked by aryantiwari92, 1 year ago

. Find the derivative of f(x) = x^2 + 1 at x = 2.​

Answers

Answered by mohit663760
0

Answer:

4

Step-by-step explanation:

d/dx=x^2+1

=2x+0

x=2

2(2)=4

Answered by Anonymous
17

Answer:

4

Step-by-step explanation:

Given :

\displaystyle \text{$f ( x ) =x^2+1$}

We have to derivative of f(x) at x = 2

First find the derivative

Using power rule here

\displaystyle \text{$x^n=n.x^{n-1}$}

\displaystyle \text{$f '( x ) =2.x^{2-1}+0$}\\\\\displaystyle \text{$f '( x ) =2.x^{1}$}\\\\\displaystyle \text{$f '( x ) =2x$}

Now at x = 2 we get

\displaystyle \text{$f '( x ) =2x$}\\\\\displaystyle \text{$f '( 2 ) =2\times2$}\\\\\displaystyle \text{$f '( 2 ) =4$}

Thus we get answer 4.

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