Math, asked by Veenamodi, 1 year ago

Find the derivative of f(x) =xsinx from first principle

Answers

Answered by aim2legend
0

f(x)=x sin x

f'(x) = x cos x + sin x

Answered by BrainlyPARCHO
0

 \mathbb{ \ \ A\ N\ S\ W\ E\ R\:  \: }

if y=f(x) g (x)

then differentiation w.r.t.x

  • dy/dx=f(x) dg(x)/dx+g(x)df(x)/dx

Now Use This

  • y=x.sinx
  • dy/dx=x.d (sinx)/dx+sinx.dx/dx
  • =x.cosx+sinx
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