Find the derivative of function Sin³x
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Answer:
a³ + b³ = (a + b)(a² - ab + b²). So, sin³ x + cos³ x = (sin x + cos x)(sin² x - sin x. cos x + cos²x).
Step-by-step explanation:
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Step-by-step explanation:
If z is any complex number and zits conjugate then prove that z-1=z conzugate /|z|²where z is not equal to zero
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