find the derivative of g(y)=(y-4)*(2y+y^2)
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Answer:
3y^2 - 4y - 8
Explanation:
dg/gy = 1×(2y + y^2) + (y - 4)×(2 +2y)
= 2y + y^2 + 2y + 2y^2 - 8 - 8y
= 3y^2 - 4y - 8
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