Math, asked by nimmonksa, 5 months ago

find the derivative of
i) 5x^4 -3/x
ii) Sec x × Tan x
iii) 1 - Cos x ÷ x^2​

Answers

Answered by Shibistarzz
0

Step-by-step explanation:

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Answered by davjangra09
0

Answer:

(I)(5/3)⅕ (II)sinx/cos²x

Step-by-step explanation:

(I)5x^4-3/x=0

5x^5-3=0

5x^5=3

x^5=3/5

x=(3/5)⅕

(II) sinx X tanx

=1/cosx X sinx/cosx

=sin/cos²x

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