Question

find the derivative of ln (√x + 1)​

Answer 1

$= = = = = >$

The function is

y= log(√x+1)

dy/dx= [1/(√x+1) (d/dx(√x+1)]

= [1/(√x+1) (1/2√x+0)]

= 1/ (2√x(√x+1))

=[ 1/( 2x+2√x)]