Question

Find the derivative of sec^-1(cosec x)

Answer 1

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Step-by-step explanation:

$let \: y = \sec^{ - 1} (cosec) \\ \\ y = \sec^{ - 1} ( \sec( \frac{\pi}{2} - x) ) \\ y = \frac{\pi}{2} - x} \\ \\ diff. \: w.r.t \: \: x \\ \\ \frac{dy}{dx} = - 1$

Here's The Answer My Friend....

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Answer 2

Answer:

f(x) = sec^-1 (cosec x)

= sec^-1 (sec(π/2-x)

= π/2-x

f'(x) = -1. ANSWER

HOPE IT IS HELPFUL TO YOU ..