Question

find the derivative of sin^-1 √1-x/1+x​

Answer 1

$y = {sin}^{ - 1} \sqrt{ \frac{1 - x}{1 + x} } \\ \\ \frac{dy}{dx} = \frac{1}{ \sqrt{1 - { (\sqrt{ \frac{1 - x}{1 + x} } })^{2} } } \\ \\ \frac{dy}{dx} = \frac{1}{ \sqrt{ \frac{1 + x - 1 + x}{1 + x} } } \\ \\ \frac{dy}{dx} = \frac{1}{ \sqrt{ \frac{2x}{1 + x} } } \\ \\ \frac{dy}{dx} = \sqrt{ \frac{1 + x}{2x} }$