Question

find the derivative of sin^-1 (2x)

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Answer 1

$let \: \: \: \: \: y = {sin}^{ - 1} 2x \\ \frac{dy}{dx} = \frac{1}{ \sqrt{1 - ( {2x})^{2} } } \\ \frac{dy}{dx} = \frac{1}{ \sqrt{1 - 4 {x}^{2} } }$