.Find the derivative of √sin(3 − 6) w.r.t x
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Answer:
Correct option is
A
−cotx
Let u=cos
3
x,v=sin
3
x
dx
du
=−3cos
2
xsinx,
dx
dv
=3sin
2
xcosx
Now,
dv
du
=
3sin
2
xcosx
−3cos
2
xsinx
=−
sinx
cosx
=−cotx
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