Question

Find the derivative of (sin x)^x +(cos x)^sin x​

Answer 1

Step-by-step explanation:

The value of cot15

∘

.cot20

∘

.cot70

∘

.cot75

∘

is

=(cot15

∘

.cot75

∘

)(cot20

∘

cot70

∘

)

Now cot75

∘

=tan15

∘

and cot70

∘

=tan20

∘

cot(90−θ)=tanθ

Therefore, the given expression can be written as

(cot15

∘

tan15

∘

)(cot20

∘

tan20

∘

)

=1×1=1