find the derivative of sinx at x=0
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x=0
.:sin(x)=sin(0)
=>sin(x)=1 [since sin(0)=1]
.:As we know that, derivative of any constant is 0 (zero)
.:derivative of 1 (one), is also 0 (zero).
.: Since sin(x)=1, therefore derivative of sin(x) is equals to 0 (zero)...[only when (x=0)].....
.:sin(x)=sin(0)
=>sin(x)=1 [since sin(0)=1]
.:As we know that, derivative of any constant is 0 (zero)
.:derivative of 1 (one), is also 0 (zero).
.: Since sin(x)=1, therefore derivative of sin(x) is equals to 0 (zero)...[only when (x=0)].....
nimmo32:
thanks a lot
brainliest please
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