Question

Find the derivative of sinx with respect to cos x

Answer 1

Hi______
let y=sinx, t=cosx
so we find dy/dt
dy/dt=dy/dx.dx/dt
dy/dx=cosx
dt/dx=-sinx
so
dy/dt=cosx/-sinx
=-cotx
hope it help u

Answer 2

y=sin X , t= cosX
..................so..............we................find ............dy/dt

.................dy/dt= dy/dx.dx/dt..................
...................dy/dx = cos X.........................
.....................dt/dx=sin X.............................
.........so...........
........................dy/dt=cos X /-sinX = - cot X......
.......may......be.......helpful...................
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