Question

Find the derivative of tan (2x+3)

Answer 1

$\huge\boxed{\fcolorbox{violet}{violet}{Answer}}$

Answer 2

Answer:

Let, y = tan (2x+3)

we need to find derivation of y.

$i.e. \: \frac{dy}{dx} = \: \frac{d \: tan(2x + 3)}{dx}$

$= {sec}^{2} (2x + 3) \times \frac{d(2x + 3)}{dx}$

${ \: as \: {(tan \: x)}^{1} = {sec}^{2} x \: }$

$= {sec}^{2} \: (2x + 3) \times 2$

$= {sec}^{2} (2x + 3)$

Musk_♥️