Question

*Find the derivative of tan(2x-3) *​

Answer 1

Hi !!

Solution Let f(x) = tan(2x+3) , u(x) = 2x + 3 = tan(2x+3) = f(x)

Thus, F is a composite of two function put t = u(x) = 2x + 3 , then dvldt = sec²t

dt/dx = 2 exist . hence, by chain rule

• df/dx = dv/dt*dt/dx = 2sec²(2x+3)

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Hope it helps you !!

@Raj❤

Answer 2

hope it helps!......................