find the derivative OF tan x
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Answer:
We know that
tan x = sin x / cos x
now differentiate both side
d/d x (tan x) = d/d x (sin x /cos x)
using formulae u/v=(u’v-v’u)/v^2
now
(cos x * cos x - (-sin x) * sin x )/cos x * cos x
=cos^2 x + sin^2 x / cos^2 x
=1 / cos ^2x
d/d x (tan x)=sec^2 x
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