Question

Find the derivative of $\purple{\sf x3^{(2x^2-1)}}$. Show all of your work and explain as much as possible.​

Answer 1

Answer:

Correct option is

C2y=cos −1 (2x 2−1)&z = cos −1x dz dd = dz/dx dy/ddx y=cos −1 (2x 2 −1)dd xd = 1−(2x 2−1) 2−1×[4x−0]

dx dd = 1−4x 2 −1+4x 2 −1∗4x = 2x 1−x 2−4x dx dd =1−x 2−2⟶1z= cos −1 dx dd = 1−x 2−1⟶2

From equation 1 and 2

dz

dy

= −1/ 1−x 2−2/ 1−x 2=2

Explanation:

mark me a brainlist