Physics, asked by SharmaShivam, 10 months ago

Find the derivative of :
S=\dfrac{4}{3\pi}sin3t+\dfrac{4}{5\pi}cos5t

Answers

Answered by Anonymous
2

Answer:

I hope we have to find the velocity in this case .

\dfrac{dS}{dt}=\dfrac{d}{dt}[\dfrac{4sin3t}{3\pi}+\dfrac{4cos5t}{5\pi}]\\\\\implies \dfrac{d}{dt}[\dfrac{20sin3t+12cos5t}{15\pi}]\\\\\implies \dfrac{60cos3t+60cos5t}{15\pi}\\\\\implies \boxed{\dfrac{4cos3t+4cos5t}{\pi}}

Note :

\dfrac{d}{dx}[sinx]=cosx

\dfrac{d}{dx}[sin(nx)]=ncos(nx)

Answered by wwwseenalingampalli
0

Answer:

hope it is helpful to you

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