Math, asked by vishu126191, 3 months ago

Find the derivative of the following function from first principal (1) (x -1) ( x -2 )​

Answers

Answered by senboni123456
1

Answer:

Step-by-step explanation:

We have,

 f(x) = (x - 1)(x - 2)={x}^{2} - 3x +2

 f^{'}(x) = \lim_{h \rarr 0}\frac{f(x + h) - f(x)}{h}\\

 f^{'}(x) = \lim_{h \rarr 0}\frac{(x + h)^{2}-3(x + h)+2 -{x}^{2} + 3x -2 }{h}\\

 f^{'}(x) = \lim_{h \rarr 0}\frac{x^{2} + h^{2} +2xh -3x - 3h+2 -{x}^{2} + 3x -2 }{h}\\

 f^{'}(x) = \lim_{h \rarr 0}\frac{ h^{2} +2xh - 3h }{h}\\

 f^{'}(x) = \lim_{h \rarr 0}(h +2x - 3)\\

 f^{'}(x) =( 2x - 3)\\

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