Question

find the derivative of the function.
y=(x-1/x) ^2​

Answer 1

Answer:

Step-by-step explanation:

first seperate the denominator

y= (1-1/x)^2

now square it,

y= 1^2 + (1/x)^2 - 2/x

now differentiate w.r.t x

dy/dx= 0+ 2(1/x)logx - 2logx

dy/dx= 2logx(1/x - 1)

hope this was helpful

and 1/x differentiation is logx...