Question

Find the derivative of the given function by Definition.

y= 1/(bt-c)^5

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Answer 1

Given  : y = 1/(bt - c)⁵

To Find : derivative

Solution:

y = 1/(bt - c)⁵

=> y = (bt - c)⁻⁵

y = (ax  + b)ⁿ

dy/dx = a(ax + b)ⁿ⁻¹

y = (bt - c)⁻⁵

=> dy/dt  =  -5(bt - c)⁻⁵⁻¹

=> dy/dt  =  -5(bt - c)⁻⁶

=> dy/dt  =  -5/(bt - c)⁶

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Answer 2

Answer :-

y = 1/(bt - c)⁵

=> y = (bt - c)⁻⁵

y = (ax  + b)ⁿ

dy/dx = a(ax + b)ⁿ⁻¹

y = (bt - c)⁻⁵

=> dy/dt  =  -5(bt - c)⁻⁵⁻¹

=> dy/dt  =  -5(bt - c)⁻⁶

=> dy/dt  =  -5/(bt - c)⁶