Find the derivative of the given functions from first principle:
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Answer:
3x²
Step-by-step explanation:
f(x) = x³ - 27
f'(x) =
= ( (x + h)³ - 27 - (x³ - 27) )/ h
= ((x + h)³ - x³ ) /h
= (x³ + h³ + 3x²h + 3xh² - x³)/h
= (3x²h + 3xh² + h³)/h
= 3x² + 3xh + h²
putting h = 0
= 3x²
f'(x) = 3x²
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