find the derivative of the inverse of a function y equals to 2 x raised to cube minus 6 x and calculate its value at x = -2
Answers
Answered by
0
Step-by-step explanation:
Given find the derivative of the inverse of a function y = 2x^3 – 6x
- Differentiating with respect to x we get
- So dy / dx = d/dx (2x^3 – 6x)
- = 2 x 3x^2 – 6
- = 6x^2 – 6
- we need to find the value of x at x = -2. So we get
- dy / dx at x = - 2 = 6 (-2)^2 – 6
- = 24 – 6
- = 18
- Now we need to find the derivative of the inverse, so we have
- dx / dy = 1 / dy / dx
- = 1 / 18
Reference link will be
https://brainly.in/question/18253410
Similar questions