find the derivative of the standard function logex by ab-initio.
thank you
:)
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Answered by
1
Hi,
Here is your answer,
y = logex
= log e + log x
y = 1 + logx base e ∴ loge value is 1
dy/dx = 1/x
Hope it helps you !
Here is your answer,
y = logex
= log e + log x
y = 1 + logx base e ∴ loge value is 1
dy/dx = 1/x
Hope it helps you !
locomaniac:
so i would just go now
bye........!! tc :)
me too. See you tomorrow.
Isske baad mee online nahi aauga.....!! Kal aauga online evening mee.
tmrw? ok
Isske baad mee online nahi aauga.....!! Kal aauga online evening mee.
ohk...............!!
ohk...............!!
Kal tight schedule hee tho day after tomorrow.
ok
Tuesday bhi tight schedule hee tho wednesday xD
not okay :(
Answered by
2
Hey !
Please refer the below attachment !
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