find the derivative of this
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dy/dx=d/dx[sin(logx)]
dy/dx=cos(logx)d/dx(logx)
dy/dx=cos(logx).1/x
dy/dx=cos(logx)/x
This is the required answer.
dy/dx=cos(logx)d/dx(logx)
dy/dx=cos(logx).1/x
dy/dx=cos(logx)/x
This is the required answer.
mawbleiwelldone:
you're welcome
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